a box is sitting on the floor. the box was then pulled with a force, ft. the box did not move. the free…

a box is sitting on the floor. the box was then pulled with a force, ft. the box did not move. the free - body diagram of the box is shown. which describes the motion of the box based on the resulting free - body diagram? it is moving up with a net force of 20 n. it is moving to the right with a net force of 10 n. it is in dynamic equilibrium with a net force of 0 n. it is in static equilibrium with a net force of 0 n. $f_n = 20n$ $f_f=-10n$ $f_t = 10n$ $f_g=-20n$

a box is sitting on the floor. the box was then pulled with a force, ft. the box did not move. the free - body diagram of the box is shown. which describes the motion of the box based on the resulting free - body diagram? it is moving up with a net force of 20 n. it is moving to the right with a net force of 10 n. it is in dynamic equilibrium with a net force of 0 n. it is in static equilibrium with a net force of 0 n. $f_n = 20n$ $f_f=-10n$ $f_t = 10n$ $f_g=-20n$

Answer

Explanation:

Step1: Calculate net - force in the horizontal direction

The horizontal forces are the pulling force $F_t = 10\ N$ and the frictional force $F_f=- 10\ N$. The net - force in the horizontal direction $F_{net,x}=F_t + F_f=10+( - 10)=0\ N$.

Step2: Calculate net - force in the vertical direction

The vertical forces are the normal force $F_N = 20\ N$ and the gravitational force $F_g=-20\ N$. The net - force in the vertical direction $F_{net,y}=F_N+F_g=20+( - 20)=0\ N$.

Step3: Determine the state of the box

Since the box is not moving and the net force acting on it is zero ($F_{net}=F_{net,x}+F_{net,y}=0\ N$), it is in static equilibrium.

Answer:

It is in static equilibrium with a net force of 0 N.