2. a box troll rolls the first half of a straight 1.8 km trail at a steady pace of 2.4 m/s east. he walks…

2. a box troll rolls the first half of a straight 1.8 km trail at a steady pace of 2.4 m/s east. he walks the second half at a constant stride of 0.5 m/s east. what is his average velocity along the trail?

2. a box troll rolls the first half of a straight 1.8 km trail at a steady pace of 2.4 m/s east. he walks the second half at a constant stride of 0.5 m/s east. what is his average velocity along the trail?

Answer

Explanation:

Step1: Calculate time for first - half

The length of the first - half of the trail $d_1=\frac{1.8\times1000}{2}=900$ m. The speed for the first - half $v_1 = 2.4$ m/s. Using the formula $t=\frac{d}{v}$, the time taken for the first - half $t_1=\frac{d_1}{v_1}=\frac{900}{2.4}=375$ s.

Step2: Calculate time for second - half

The length of the second - half of the trail $d_2 = 900$ m. The speed for the second - half $v_2=0.5$ m/s. Using the formula $t=\frac{d}{v}$, the time taken for the second - half $t_2=\frac{d_2}{v_2}=\frac{900}{0.5}=1800$ s.

Step3: Calculate total time and total displacement

The total displacement $d = 1.8\times1000$ m (since it's a straight - line motion). The total time $t=t_1 + t_2=375+1800 = 2175$ s.

Step4: Calculate average velocity

Using the formula for average velocity $v_{avg}=\frac{d}{t}$, we have $v_{avg}=\frac{1.8\times1000}{2175}\approx0.83$ m/s east.

Answer:

Approximately $0.83$ m/s east