if a box weighing 520 n is hung from a spring whose constant is 650 n/m, how many centimeters will the…
if a box weighing 520 n is hung from a spring whose constant is 650 n/m, how many centimeters will the spring stretch? cm
Answer
Explanation:
Step1: Recall Hooke's Law
$F = kx$, where $F$ is the force, $k$ is the spring - constant, and $x$ is the displacement. We need to solve for $x$.
Step2: Rearrange the formula for $x$
$x=\frac{F}{k}$. Given $F = 520\ N$ and $k = 650\ N/m$. $x=\frac{520\ N}{650\ N/m}=0.8\ m$.
Step3: Convert meters to centimeters
Since $1\ m = 100\ cm$, then $x = 0.8\ m\times100\ cm/m = 80\ cm$.
Answer:
80