bruce collects the data on four electric circuits listed in the table.\n|circuit|voltage (v)|resistance…

bruce collects the data on four electric circuits listed in the table.\n|circuit|voltage (v)|resistance (ω)|\n|----|----|----|\n|w|18|38|\n|x|24|34|\n|y|34|70|\n|z|12|18|\nbruce must report any circuits that deliver more than 4.0 c of charge in 8.0 s.\nwhich lists every circuit that bruce must include in his report?\no x and z\no x and y\no w and y\no w and z

Answer

Explanation:

Step1: Use Ohm's law to find current

Ohm's law is $I=\frac{V}{R}$, where $I$ is current, $V$ is voltage and $R$ is resistance.

Step2: Use $Q = It$ to find charge

$Q$ is charge, $I$ is current and $t$ is time. Given $t = 8.0\ s$.

For Circuit W:

$I_W=\frac{V_W}{R_W}=\frac{18}{38}\ A$ $Q_W=I_Wt=\frac{18}{38}\times8.0\ C\approx3.8\ C$

For Circuit X:

$I_X=\frac{V_X}{R_X}=\frac{24}{34}\ A$ $Q_X=I_Xt=\frac{24}{34}\times8.0\ C\approx5.6\ C$

For Circuit Y:

$I_Y=\frac{V_Y}{R_Y}=\frac{34}{70}\ A$ $Q_Y=I_Yt=\frac{34}{70}\times8.0\ C\approx3.9\ C$

For Circuit Z:

$I_Z=\frac{V_Z}{R_Z}=\frac{12}{18}\ A$ $Q_Z=I_Zt=\frac{12}{18}\times8.0\ C\approx5.3\ C$

Answer:

X and Z