calculate the following: (48.98 ± 4.11) km/h + (15.24 ± 4.44) km/h. round based on the applicable rules of…

calculate the following: (48.98 ± 4.11) km/h + (15.24 ± 4.44) km/h. round based on the applicable rules of accuracy/precision. answer = ( ± ) km/h. question 7 determine the current, i, (in amps) given the following: v = 220 v ±2.2 % and r = 830ω ± 1.3 %. round based on the applicable rules of accuracy/precision. i = v/r = select an answer ± %
Answer
Explanation:
Step1: Add the values without uncertainties
$48.98 + 15.24=64.22$
Step2: Add the uncertainties
$4.11 + 4.44 = 8.55$
Step3: Round the sum and uncertainty
Rounding $64.22$ to two decimal - places gives $64.22$ (since there are no specific rounding - off rules other than general decimal - place rules mentioned). Rounding $8.55$ to two decimal - places gives $8.55$.
Answer:
$(64.22\pm8.55)$ km/h
Explanation for Question 7:
Step1: Calculate the nominal value of the current
$I=\frac{V}{R}=\frac{220}{830}\approx0.265$ A
Step2: Calculate the relative uncertainty in current
The relative uncertainty in a quotient $\frac{V}{R}$ is given by $\frac{\Delta I}{I}=\sqrt{(\frac{\Delta V}{V})^2+(\frac{\Delta R}{R})^2}$. $\frac{\Delta V}{V}=2.2% = 0.022$ and $\frac{\Delta R}{R}=1.3%=0.013$. $\frac{\Delta I}{I}=\sqrt{(0.022)^2+(0.013)^2}=\sqrt{0.000484 + 0.000169}=\sqrt{0.000653}\approx0.0256$ or $2.56%$
Step3: Calculate the uncertainty in current
$\Delta I = I\times\frac{\Delta I}{I}=0.265\times0.0256\approx0.0068$ A
Answer:
$I = 0.265\pm0.007$ A (rounded to three decimal - places for the value of current and three significant figures for the uncertainty) and $2.6%$ (rounded to one decimal - place for the relative uncertainty)