3. calculate the specific heat capacity of a piece of wood if 1500.0 g of the wood absorbs 67,500 joules of…

Explanation:

Step1: Identify the formula

The formula for heat $Q = mc\Delta T$, where $Q$ is heat, $m$ is mass, $c$ is specific - heat capacity, and $\Delta T$ is change in temperature. We need to solve for $c$, so $c=\frac{Q}{m\Delta T}$.

Step2: Calculate the change in temperature

$\Delta T=T_2 - T_1$. Given $T_1 = 32^{\circ}C$ and $T_2 = 57^{\circ}C$, then $\Delta T=57 - 32=25^{\circ}C$.

Step3: Substitute values into the formula

We know $Q = 67500\ J$, $m = 1500.0\ g$, and $\Delta T = 25^{\circ}C$. Substituting into $c=\frac{Q}{m\Delta T}$, we get $c=\frac{67500}{1500.0\times25}$.

Step4: Calculate the specific - heat capacity

$c=\frac{67500}{1500.0\times25}=\frac{67500}{37500}=1.8\ J/(g\cdot^{\circ}C)$.

Answer:

$1.8\ J/(g\cdot^{\circ}C)$