calculate the torque produced by a 50 - n perpendicular force at the end of a 0.25 - m - long wrench…

calculate the torque produced by a 50 - n perpendicular force at the end of a 0.25 - m - long wrench. express your answer in newton - meters.\nτ = n·m

calculate the torque produced by a 50 - n perpendicular force at the end of a 0.25 - m - long wrench. express your answer in newton - meters.\nτ = n·m

Answer

Explanation:

Step1: Recall torque formula

The formula for torque $\tau$ when the force $F$ is perpendicular to the lever - arm $r$ is $\tau = rF$.

Step2: Identify given values

We are given that $F = 50\ N$ and $r=0.25\ m$.

Step3: Calculate torque

Substitute the values into the formula: $\tau=(0.25\ m)\times(50\ N)$. $\tau = 12.5\ N\cdot m$

Answer:

$12.5$