calculate the volume that a 0.323 - mol sample of a gas will occupy at 265 k and a pressure of 0.900 atm.

Answer:

7.18 L

Explanation:

Step1: Recall ideal - gas law

$PV = nRT$

Step2: Solve for volume $V$

$V=\frac{nRT}{P}$

Step3: Identify values

$n = 0.323\ mol$, $R=0.0821\ L\cdot atm/(mol\cdot K)$, $T = 265\ K$, $P = 0.900\ atm$

Step4: Substitute values

$V=\frac{0.323\ mol\times0.0821\ L\cdot atm/(mol\cdot K)\times265\ K}{0.900\ atm}$

Step5: Calculate

$V = 7.18\ L$