calculating the acceleration of a train\nuntil a train is a safe distance from the station, it must travel…

calculating the acceleration of a train\nuntil a train is a safe distance from the station, it must travel at 5 m/s. once the train is on open track, it can speed up to 45 m/s. if it takes a train 8 seconds to reach 45 m/s, what is the acceleration of the train?\n$\\text{______} \\text{ m/s}^2$

calculating the acceleration of a train\nuntil a train is a safe distance from the station, it must travel at 5 m/s. once the train is on open track, it can speed up to 45 m/s. if it takes a train 8 seconds to reach 45 m/s, what is the acceleration of the train?\n$\\text{______} \\text{ m/s}^2$

Answer

Explanation:

Step1: Identify the formula

The formula for acceleration is $a=\frac{v - u}{t}$, where $a$ is acceleration, $v$ is final - velocity, $u$ is initial - velocity, and $t$ is time.

Step2: Determine the values

The initial velocity $u = 5\ m/s$, the final velocity $v = 45\ m/s$, and the time $t = 8\ s$.

Step3: Substitute values into formula

$a=\frac{45 - 5}{8}=\frac{40}{8}$

Step4: Calculate the result

$a = 5\ m/s^{2}$

Answer:

$5$