calculating current in a parallel circuit\nwhat is the current in each branch of the circuit?\n8 ω: a\n10 ω…

Explanation:

Step1: Apply Ohm's law

Ohm's law is $I = \frac{V}{R}$, where $I$ is current, $V$ is voltage and $R$ is resistance. In a parallel - circuit, the voltage across each branch is the same as the source voltage. Here, $V = 60.0\ V$.

Step2: Calculate current for 8 - Ω branch

For the $8.0\ \Omega$ resistor, $I_1=\frac{V}{R_1}$. Substitute $V = 60.0\ V$ and $R_1 = 8.0\ \Omega$ into the formula: $I_1=\frac{60.0}{8.0}=7.5\ A$.

Step3: Calculate current for 10 - Ω branch

For the $10.0\ \Omega$ resistor, $I_2=\frac{V}{R_2}$. Substitute $V = 60.0\ V$ and $R_2 = 10.0\ \Omega$ into the formula: $I_2=\frac{60.0}{10.0}=6.0\ A$.

Step4: Calculate current for 12 - Ω branch

For the $12.0\ \Omega$ resistor, $I_3=\frac{V}{R_3}$. Substitute $V = 60.0\ V$ and $R_3 = 12.0\ \Omega$ into the formula: $I_3=\frac{60.0}{12.0}=5.0\ A$.

Answer:

8 Ω: 7.5 A 10 Ω: 6.0 A 12 Ω: 5.0 A