calculating current\nat the test station you will test the current at points a and b on the first circuit…

calculating current\nat the test station you will test the current at points a and b on the first circuit shown below. then you will remove one of the 5ω resistors and determine the current at point c.\noriginal resistor removed\nwhat will the current be at point a in the original circuit?\nwhat will the current be at point b in the original circuit?

calculating current\nat the test station you will test the current at points a and b on the first circuit shown below. then you will remove one of the 5ω resistors and determine the current at point c.\noriginal resistor removed\nwhat will the current be at point a in the original circuit?\nwhat will the current be at point b in the original circuit?

Answer

Explanation:

Step1: Calculate total resistance in original circuit

In a series - circuit, the total resistance $R_{total}$ is the sum of individual resistances. So, $R_{total}=5 + 5+28.7=38.7\Omega$.

Step2: Use Ohm's law to find current in original circuit

Ohm's law is $I = \frac{V}{R}$, where $V = 2.72V$ and $R = R_{total}=38.7\Omega$. So, $I=\frac{2.72}{38.7}\approx0.07A$. In a series - circuit, the current is the same at all points.

Answer:

  • What will the current be at point A in the original circuit? $0.07A$
  • What will the current be at point B in the original circuit? $0.07A$