calculating electrical force what is the electrical force between q2 and q3? recall that k = 8.99×10^9…

calculating electrical force what is the electrical force between q2 and q3? recall that k = 8.99×10^9 n·m²/c². q1 = +6 c q2 = -4 c q3 = +3 c 1.0×10^11 n -1.1×10^11 n -1.6×10^11 n 1.8×10^11 n

calculating electrical force what is the electrical force between q2 and q3? recall that k = 8.99×10^9 n·m²/c². q1 = +6 c q2 = -4 c q3 = +3 c 1.0×10^11 n -1.1×10^11 n -1.6×10^11 n 1.8×10^11 n

Answer

Explanation:

Step1: Identify Coulomb's law formula

$F = k\frac{|q_1q_2|}{r^{2}}$

Step2: Substitute values

Here, $k = 8.99\times 10^{9}\ N\cdot\frac{m^{2}}{C^{2}}$, $q_1 = - 4\ C$, $q_2=+3\ C$, $r = 1\ m$. $F=8.99\times 10^{9}\times\frac{|(-4)\times(3)|}{1^{2}}$

Step3: Calculate the force

$F = 8.99\times10^{9}\times12\approx1.1\times 10^{11}\ N$. Since the charges have opposite - signs, the force is attractive, so $F=- 1.1\times 10^{11}\ N$.

Answer:

$-1.1\times 10^{11}\ N$