calculating horizontal velocity\na tornado lifts a truck 252 m above the ground. as the storm continues, the…

calculating horizontal velocity\na tornado lifts a truck 252 m above the ground. as the storm continues, the tornado throws the truck horizontally. it lands 560 m away from where it was picked up.\nhow fast was the truck traveling horizontally through its flight? round your answer to the nearest tenth.\n______ m/s

calculating horizontal velocity\na tornado lifts a truck 252 m above the ground. as the storm continues, the tornado throws the truck horizontally. it lands 560 m away from where it was picked up.\nhow fast was the truck traveling horizontally through its flight? round your answer to the nearest tenth.\n______ m/s

Answer

Explanation:

Step1: Find time of - fall

The vertical - motion of the truck is a free - fall motion. The vertical displacement $y = 252$ m, and the initial vertical velocity $u_y=0$ m/s. Using the equation $y = u_y t+\frac{1}{2}gt^{2}$, since $u_y = 0$ m/s, we have $y=\frac{1}{2}gt^{2}$. Solving for $t$: $t=\sqrt{\frac{2y}{g}}$ where $g = 9.8$ m/s² and $y = 252$ m. $t=\sqrt{\frac{2\times252}{9.8}}\approx\sqrt{\frac{504}{9.8}}\approx\sqrt{51.43}\approx7.17$ s

Step2: Calculate horizontal velocity

The horizontal displacement $x = 560$ m. The horizontal velocity $v_x$ is constant (no horizontal acceleration in the absence of air - resistance). Using the formula $v_x=\frac{x}{t}$. $v_x=\frac{560}{7.17}\approx78.1$ m/s

Answer:

$78.1$ m/s