calculating net force - p. 19\nnet force\nforces: going in the same direction, going in opposite directions…

calculating net force - p. 19\nnet force\nforces: going in the same direction, going in opposite directions, equal and opposite\ncalculation\ndirections: calculate the net forces acting on the objects described below. circle the number of any problem that results in no motion.\n1.\n5 n 5 n\n2.\n3 n 5 n\n3. which team will push the box farther?\nteam 1 team 2\n5 n 5 n 5 n 5 n 12 n\n4. sally is pushing a shopping cart with a force of 20 n. because the wheels are stuck, the friction caused by the ground is exerting a force of 8 n in the opposite direction. calculate the net force on the shopping cart, including an arrow indicating what direction the shopping cart is going.\n20 n 8 n\n5. jeff is pushing a rock up a hill with a force of 85 n. if chris comes to help and chris can push with a force of 60 n, what is the net force on the rock?\n85 n 60 n

calculating net force - p. 19\nnet force\nforces: going in the same direction, going in opposite directions, equal and opposite\ncalculation\ndirections: calculate the net forces acting on the objects described below. circle the number of any problem that results in no motion.\n1.\n5 n 5 n\n2.\n3 n 5 n\n3. which team will push the box farther?\nteam 1 team 2\n5 n 5 n 5 n 5 n 12 n\n4. sally is pushing a shopping cart with a force of 20 n. because the wheels are stuck, the friction caused by the ground is exerting a force of 8 n in the opposite direction. calculate the net force on the shopping cart, including an arrow indicating what direction the shopping cart is going.\n20 n 8 n\n5. jeff is pushing a rock up a hill with a force of 85 n. if chris comes to help and chris can push with a force of 60 n, what is the net force on the rock?\n85 n 60 n

Answer

Explanation:

Step1: Calculate net - force for problem 1

When two forces of 5 N act in opposite directions on an object, the net force $F_{net}=5 - 5=0$ N.

Step2: Calculate net - force for problem 2

Two forces act on the object, 3 N and 5 N in opposite directions. The net force $F_{net}=5 - 3 = 2$ N.

Step3: Determine the winning team in problem 3

For Team 1, the net force is $5+5 + 5-5=10$ N. For Team 2, the net force is 12 N. Since $12>10$, Team 2 will push the box farther.

Step4: Calculate net - force for problem 4

Sally exerts a force of 20 N and friction exerts 8 N in the opposite direction. The net force $F_{net}=20 - 8=12$ N, and the direction is to the right (the direction Sally is pushing).

Step5: Calculate net - force for problem 5

Jeff exerts a force of 85 N and Chris exerts a force of 60 N in the same direction. The net force $F_{net}=85 + 60=145$ N.

Answer:

  1. 0 N
  2. 2 N
  3. Team 2
  4. 12 N to the right
  5. 145 N