calculating net force\nwhat is the magnitude and direction (right or left) of the net force acting on the…

calculating net force\nwhat is the magnitude and direction (right or left) of the net force acting on the box?\n$f_n = 12\\ n$\n$f_p = 15\\ n$\n$f_f = 3\\ n$\n$f_g = 12\\ n$

calculating net force\nwhat is the magnitude and direction (right or left) of the net force acting on the box?\n$f_n = 12\\ n$\n$f_p = 15\\ n$\n$f_f = 3\\ n$\n$f_g = 12\\ n$

Answer

Answer:

12 N to the right

Explanation:

Step1: Analyze horizontal forces

Forces acting horizontally are $F_p = 15$ N (right - ward) and $F_f=3$ N (left - ward).

Step2: Calculate net horizontal force

$F_{net - x}=F_p - F_f=15 - 3=12$ N.

Step3: Analyze vertical forces

Vertical forces $F_N = 12$ N (up - ward) and $F_g = 12$ N (down - ward) cancel each other out ($F_{net - y}=F_N - F_g=12 - 12 = 0$ N). So the net force is the net horizontal force, which is 12 N to the right.