calculating volume\nif the diameter of the black marble is 3.0 cm, and by using the formula for volume, what…

calculating volume\nif the diameter of the black marble is 3.0 cm, and by using the formula for volume, what is a good approximation of its volume? record to the ones place.\n$\\text{______} \\text{cm}^3$\ndetermine the initial volume of water in the graduated cylinder. if you added the black marble to the graduated cylinder and it sinks, what final volume should the water level indicate? record to the ones place.\n$\\text{______} \\text{ml}$
Answer
Explanation:
Step1: Find the radius of the marble
The radius $r$ of a circle is half of the diameter $d$. Given $d = 3.0$ cm, so $r=\frac{d}{2}=\frac{3.0}{2}=1.5$ cm.
Step2: Calculate the volume of the marble
The volume $V$ of a sphere is given by the formula $V = \frac{4}{3}\pi r^{3}$. Substitute $r = 1.5$ cm into the formula: [ \begin{align*} V&=\frac{4}{3}\pi(1.5)^{3}\ &=\frac{4}{3}\pi\times3.375\ &=4.5\pi\ &\approx4.5\times 3.14\ & = 14.13\approx14\text{ cm}^3 \end{align*} ]
Step3: Determine the initial volume of water
From the graduated - cylinder, the initial volume of water $V_{i}=100$ mL.
Step4: Calculate the final volume of water
The final volume $V_{f}$ of water after adding the marble is the sum of the initial volume of water $V_{i}$ and the volume of the marble $V$. So $V_{f}=V_{i}+V$. Since $V_{i} = 100$ mL and $V\approx14$ cm$^{3}$ (and $1$ cm$^{3}=1$ mL), $V_{f}=100 + 14=114$ mL.
Answer:
14 114