4. a car increases its speed from 9.6 meters per second to 11.2 meters per second in 4.0 seconds. what is…

4. a car increases its speed from 9.6 meters per second to 11.2 meters per second in 4.0 seconds. what is the average acceleration of the car during this 4 - second interval? 0.40 m/s² 2.4 m/s² 2.8 m/s² 5.2 m/s² clear all

4. a car increases its speed from 9.6 meters per second to 11.2 meters per second in 4.0 seconds. what is the average acceleration of the car during this 4 - second interval? 0.40 m/s² 2.4 m/s² 2.8 m/s² 5.2 m/s² clear all

Answer

Explanation:

Step1: Identify the formula for acceleration

The formula for average acceleration $a$ is $a=\frac{v_f - v_i}{t}$, where $v_f$ is the final velocity, $v_i$ is the initial velocity, and $t$ is the time - interval.

Step2: Substitute the given values

Given $v_i = 9.6\ m/s$, $v_f=11.2\ m/s$, and $t = 4.0\ s$. Then $a=\frac{11.2 - 9.6}{4.0}$.

Step3: Calculate the numerator

$11.2−9.6 = 1.6\ m/s$.

Step4: Calculate the acceleration

$a=\frac{1.6}{4.0}=0.4\ m/s^2$.

Answer:

$0.40\ m/s^2$