under certain conditions, oxygen gas (o₂) has a density of 0.00134 g/ml. find the volume occupied by 250.0 g…
under certain conditions, oxygen gas (o₂) has a density of 0.00134 g/ml. find the volume occupied by 250.0 g of o₂ under the same conditions.
Answer
Explanation:
Step1: Recall density formula
Density ($\rho$) = $\frac{mass(m)}{volume(V)}$, so $V=\frac{m}{\rho}$.
Step2: Substitute values
Given $m = 250.0$ g and $\rho=0.00134$ g/mL. Then $V=\frac{250.0}{0.00134}$.
Step3: Calculate volume
$V=\frac{250.0}{0.00134}\approx186567.16$ mL.
Answer:
186567.16 mL