which change will decrease the electric force between two positively charged objects?\nmoving them closer…

which change will decrease the electric force between two positively charged objects?\nmoving them closer together\nmoving them farther apart\nadding neutrons\nremoving electrons

which change will decrease the electric force between two positively charged objects?\nmoving them closer together\nmoving them farther apart\nadding neutrons\nremoving electrons

Answer

Explanation:

Step1: Recall Coulomb's law

Coulomb's law is (F = k\frac{q_1q_2}{r^{2}}), where (F) is the electric force, (k) is the Coulomb constant, (q_1) and (q_2) are the charges of the two objects, and (r) is the distance between them.

Step2: Analyze each option

  • Moving them closer together: If (r) decreases, according to (F = k\frac{q_1q_2}{r^{2}}), (F) will increase.
  • Moving them farther apart: If (r) increases, according to (F = k\frac{q_1q_2}{r^{2}}), (F) will decrease.
  • Adding neutrons: Neutrons are neutral ((q = 0)), so adding neutrons does not change (q_1) and (q_2), and (F) remains unchanged.
  • Removing electrons: For positively - charged objects, removing electrons will increase the positive charge (since (q= N_{p}-N_{e}), where (N_{p}) is the number of protons and (N_{e}) is the number of electrons). If (q_1) and/or (q_2) increase, according to (F = k\frac{q_1q_2}{r^{2}}), (F) will increase.

Answer:

moving them farther apart