what is the change in heat of a 3.25 - kilogram block of aluminum when its temperature decreases from -1.0°c…

what is the change in heat of a 3.25 - kilogram block of aluminum when its temperature decreases from -1.0°c to -15.5°c? the specific heat of aluminum is 0.897 j/g°c. round your answer to the correct number of significant figures. joules complete the sentence. this process is because heat is by the aluminum as it cools.

what is the change in heat of a 3.25 - kilogram block of aluminum when its temperature decreases from -1.0°c to -15.5°c? the specific heat of aluminum is 0.897 j/g°c. round your answer to the correct number of significant figures. joules complete the sentence. this process is because heat is by the aluminum as it cools.

Answer

Explanation:

Step1: Convert mass to grams

$m = 3.25\ kg\times1000\ g/kg=3250\ g$

Step2: Calculate temperature change

$\Delta T=T_{final}-T_{initial}=- 15.5^{\circ}C-(-1.0^{\circ}C)=-14.5^{\circ}C$

Step3: Use heat - change formula

The formula for heat change is $Q = mc\Delta T$, where $m$ is mass, $c$ is specific heat, and $\Delta T$ is temperature change. $Q=(3250\ g)\times(0.897\ J/g^{\circ}C)\times(-14.5^{\circ}C)$ $Q = 3250\times0.897\times(- 14.5)\ J$ $Q=-41939.625\ J\approx - 41900\ J$ (rounded to 3 significant figures) The process is exothermic because heat is released by the aluminum as it cools.

Answer:

-41900; exothermic; released