what is the change in heat of a 5.57 - kilogram block of aluminum when its temperature increases from - 28°c…

what is the change in heat of a 5.57 - kilogram block of aluminum when its temperature increases from - 28°c to - 19°c? the specific heat of aluminum is 0.897 j/g°c. round your answer to the correct number of significant figures. joules complete the sentence. this process is because heat is by the aluminum.
Answer
Explanation:
Step1: Convert mass to grams
$m = 5.57\ kg\times1000\ g/kg= 5570\ g$
Step2: Calculate temperature change
$\Delta T=T_2 - T_1=- 19^{\circ}C-(-28^{\circ}C)=9^{\circ}C$
Step3: Use heat - change formula
$Q = mc\Delta T$, where $c = 0.897\ J/g^{\circ}C$, $m = 5570\ g$, $\Delta T=9^{\circ}C$ $Q=5570\ g\times0.897\ J/g^{\circ}C\times9^{\circ}C$ $Q = 5570\times0.897\times9\ J$ $Q=44939.61\ J\approx4.49\times 10^{4}\ J$
Step4: Determine heat - transfer nature
The process is endothermic because heat is absorbed by the aluminum.
Answer:
$4.49\times 10^{4}$ joules This process is endothermic because heat is absorbed by the aluminum.