a charge of 6.4×10⁻⁷ c experiences an electric force of 1.8×10⁻¹ n. what is the electric field…

a charge of 6.4×10⁻⁷ c experiences an electric force of 1.8×10⁻¹ n. what is the electric field strength?\n1.1×10⁻⁷ n/c\n3.6×10⁻⁶ n/c\n8.2×10⁰ n/c\n2.8×10⁵ n/c

a charge of 6.4×10⁻⁷ c experiences an electric force of 1.8×10⁻¹ n. what is the electric field strength?\n1.1×10⁻⁷ n/c\n3.6×10⁻⁶ n/c\n8.2×10⁰ n/c\n2.8×10⁵ n/c

Answer

Answer:

D. $2.8\times 10^{5}\text{ N/C}$

Explanation:

Step1: Recall the formula

The formula for electric - field strength is $E=\frac{F}{q}$, where $E$ is the electric - field strength, $F$ is the electric force, and $q$ is the charge.

Step2: Substitute the given values

Given $F = 1.8\times10^{-1}\text{ N}$ and $q=6.4\times 10^{-7}\text{ C}$. Then $E=\frac{1.8\times 10^{-1}}{6.4\times 10^{-7}}$.

Step3: Calculate the result

Using the rule of exponents $\frac{a^m}{a^n}=a^{m - n}$, we have $E=\frac{1.8}{6.4}\times10^{-1-(-7)}=\frac{1.8}{6.4}\times10^{6}$. $\frac{1.8}{6.4}\approx0.28$, and $0.28\times10^{6}=2.8\times 10^{5}\text{ N/C}$.