the chart shows the time, initial velocity, and final velocity of three riders.\n| rider | time | initial…

the chart shows the time, initial velocity, and final velocity of three riders.\n| rider | time | initial velocity | final velocity |\n| gabriella | 10 sec | 55 | 32 |\n| franklin | 8.5 sec | 50 | 50 |\n| kendall | 6 sec | 53.2 | 67 |\nwhich best describes the riders final velocities?\ngabriella is speeding up at the same rate that kendall is slowing down, and franklin is not accelerating.\ngabriella is slowing down at the same rate that kendall is speeding up, and franklin is not accelerating.\ngabriella and franklin are both slowing down, and kendall is accelerating.\ngabriella is slowing down, and kendall and franklin are accelerating.
Answer
Answer:
Gabriella is slowing down at the same rate that Kendall is speeding up, and Franklin is not accelerating.
Explanation:
Step1: Calculate Gabriella's acceleration
Acceleration formula is $a=\frac{v_f - v_i}{t}$. For Gabriella, $v_i = 55$, $v_f=32$, $t = 10$. So $a_{Gabriella}=\frac{32 - 55}{10}=\frac{- 23}{10}=-2.3$.
Step2: Calculate Franklin's acceleration
For Franklin, $v_i = 50$, $v_f = 50$, $t=8.5$. So $a_{Franklin}=\frac{50 - 50}{8.5}=0$.
Step3: Calculate Kendall's acceleration
For Kendall, $v_i = 53.2$, $v_f = 67$, $t = 6$. So $a_{Kendall}=\frac{67 - 53.2}{6}=\frac{13.8}{6}=2.3$.
Step4: Analyze the results
The magnitude of Gabriella's acceleration ($2.3$) is the same as Kendall's acceleration magnitude, but Gabriella has negative acceleration (slowing - down) and Kendall has positive acceleration (speeding - up). Franklin has zero acceleration (not accelerating).