a circuit with a 12.0 v battery is attached to an 80.0 ω resistor. what is the current of the circuit? 80.0…
a circuit with a 12.0 v battery is attached to an 80.0 ω resistor. what is the current of the circuit? 80.0 ω 12.0 v i = ? a
Answer
Explanation:
Step1: Recall Ohm's law
$V = IR$, where $V$ is voltage, $I$ is current and $R$ is resistance. We need to solve for $I$.
Step2: Rearrange the formula for $I$
$I=\frac{V}{R}$
Step3: Substitute given values
Given $V = 12.0\ V$ and $R=80.0\ \Omega$, then $I=\frac{12.0}{80.0}$ $I = 0.15\ A$
Answer:
$0.15$