which circuits correctly show ohms law?

Explanation:

Step1: Recall Ohm's law formula

Ohm's law is $V = IR$, where $V$ is voltage, $I$ is current, and $R$ is resistance.

Step2: Check the first - circuit

For the first circuit, $V = 25V$, $I = 5A$, $R = 5\Omega$. Using $V=IR$, we have $5A\times5\Omega=25V$, so it satisfies Ohm's law.

Step3: Check the second - circuit

For the second circuit, $V = 18V$, $I = 6A$, $R = 4\Omega$. Using $V = IR$, we get $6A\times4\Omega = 24V\neq18V$, so it does not satisfy Ohm's law.

Step4: Check the third - circuit

For the third circuit, $V = 56V$, $I = 7A$, $R = 8\Omega$. Using $V = IR$, we have $7A\times8\Omega=56V$, so it satisfies Ohm's law.

Step5: Check the fourth - circuit

For the fourth circuit, $V = 20V$, $I = 5A$, $R = 4\Omega$. Using $V = IR$, we get $5A\times4\Omega = 20V$, so it satisfies Ohm's law.

Answer:

The first, third, and fourth circuits correctly show Ohm's law.