complete combustion of a 0.600 - g sample of a compound in a bomb calorimeter releases 24.0 kj of heat. the…
complete combustion of a 0.600 - g sample of a compound in a bomb calorimeter releases 24.0 kj of heat. the bomb calorimeter has a mass of 1.30 kg and a specific heat of 3.41 j/(g,°c). if the initial temperature of the calorimeter is 25.5°c, what is its final temperature? use $q = mc_pdelta t$.\n30.9°c\n34.5°c\n44.0°c\n51.5°c
Answer
Explanation:
Step1: Convert heat to joules
$q = 24.0\ kJ=24000\ J$
Step2: Convert mass to grams
$m = 1.30\ kg = 1300\ g$
Step3: Rearrange the heat - capacity formula for $\Delta T$
$\Delta T=\frac{q}{mC_p}$ Substitute $q = 24000\ J$, $m = 1300\ g$ and $C_p=3.41\ J/(g^{\circ}C)$ into the formula: $\Delta T=\frac{24000}{1300\times3.41}\approx5.4^{\circ}C$
Step4: Calculate the final temperature
$T_f=T_i+\Delta T$ Given $T_i = 25.5^{\circ}C$, then $T_f=25.5 + 5.4=30.9^{\circ}C$
Answer:
$30.9^{\circ}C$