a conducting bar moves along a circuit with a constant velocity. a constant magnetic field of 1.23 t is…

a conducting bar moves along a circuit with a constant velocity. a constant magnetic field of 1.23 t is perpendicular to the bar and circuit. the bar covers 2.00 m² of area in 1.00 second. what is the emf induced in the circuit? ? v

a conducting bar moves along a circuit with a constant velocity. a constant magnetic field of 1.23 t is perpendicular to the bar and circuit. the bar covers 2.00 m² of area in 1.00 second. what is the emf induced in the circuit? ? v

Answer

Explanation:

Step1: Recall Faraday's law

The formula for induced EMF is $\mathcal{E}=B\frac{\Delta A}{\Delta t}$, where $B$ is the magnetic - field strength, $\Delta A$ is the change in area, and $\Delta t$ is the change in time.

Step2: Identify given values

We are given that $B = 1.23\ T$, $\Delta A=2.00\ m^{2}$, and $\Delta t = 1.00\ s$.

Step3: Calculate the induced EMF

Substitute the values into the formula: $\mathcal{E}=1.23\times\frac{2.00}{1.00}$. $\mathcal{E}=2.46\ V$

Answer:

$2.46$