consider the nuclear equation below.\n$_{11}^{22}na\\longrightarrow_{10}^{22}ne + _{?}^{0}\\beta$\nwhich is…
consider the nuclear equation below.\n$_{11}^{22}na\\longrightarrow_{10}^{22}ne + _{?}^{0}\\beta$\nwhich is the missing value that will balance the equation?\n-1\n0\n+1\n+2
Answer
Explanation:
Step1: Analyze mass - number balance
In a nuclear equation, the sum of mass - numbers on the left - hand side must equal the sum of mass - numbers on the right - hand side. Here, the mass - number of $^{22}{11}Na$ is 22, and the mass - number of $^{22}{10}Ne$ is 22 and for $\beta$ particle it is 0. So, $22=22 + 0$ (mass - number is balanced).
Step2: Analyze atomic - number balance
The atomic number of $^{22}{11}Na$ is 11, and the atomic number of $^{22}{10}Ne$ is 10. Let the atomic number of the $\beta$ particle be $x$. Then, $11=10 + x$.
Step3: Solve for $x$
Solving the equation $11 = 10+x$ for $x$, we get $x=11 - 10=1$.
Answer:
+1