consider the nuclear equation below.\n$_{56}^{124}ba\\longrightarrow_{55}^{124}cs +?$ \nwhich completes the…

consider the nuclear equation below.\n$_{56}^{124}ba\\longrightarrow_{55}^{124}cs +?$ \nwhich completes the nuclear equation?\n$_{+1}^{0}e$\n$_{-1}^{0}e$\n$_{0}^{1}n$\n$_{1}^{1}h$

consider the nuclear equation below.\n$_{56}^{124}ba\\longrightarrow_{55}^{124}cs +?$ \nwhich completes the nuclear equation?\n$_{+1}^{0}e$\n$_{-1}^{0}e$\n$_{0}^{1}n$\n$_{1}^{1}h$

Answer

Explanation:

Step1: Analyze mass - number conservation

In a nuclear equation, the sum of mass - numbers on the left - hand side must equal the sum of mass - numbers on the right - hand side. The mass - number of $^{124}{56}Ba$ is 124, and the mass - number of $^{124}{55}Cs$ is 124. So the mass - number of the unknown particle is $124−124 = 0$.

Step2: Analyze atomic - number conservation

The sum of atomic numbers on the left - hand side must equal the sum of atomic numbers on the right - hand side. The atomic number of $^{124}{56}Ba$ is 56, and the atomic number of $^{124}{55}Cs$ is 55. So the atomic number of the unknown particle is $56 - 55=1$.

Answer:

$^{0}_{+ 1}e$