consider the nuclear equation below.\n$_{94}^{239}pu\\longrightarrow x + _{2}^{4}he$\nwhat is…

consider the nuclear equation below.\n$_{94}^{239}pu\\longrightarrow x + _{2}^{4}he$\nwhat is x?\n$_{96}^{235}cm$\n$_{92}^{243}u$\n$_{92}^{235}u$\n$_{96}^{243}cm$

consider the nuclear equation below.\n$_{94}^{239}pu\\longrightarrow x + _{2}^{4}he$\nwhat is x?\n$_{96}^{235}cm$\n$_{92}^{243}u$\n$_{92}^{235}u$\n$_{96}^{243}cm$

Answer

Explanation:

Step1: Apply mass - number conservation

In a nuclear equation, the sum of mass - numbers on the left - hand side equals the sum of mass - numbers on the right - hand side. The mass - number of (^{239}{94}Pu) is 239 and the mass - number of (^{4}{2}He) is 4. Let the mass - number of (X) be (A). Then (239=A + 4), so (A=239 - 4=235).

Step2: Apply atomic - number conservation

The sum of atomic numbers on the left - hand side equals the sum of atomic numbers on the right - hand side. The atomic number of (^{239}{94}Pu) is 94 and the atomic number of (^{4}{2}He) is 2. Let the atomic number of (X) be (Z). Then (94=Z + 2), so (Z=94 - 2 = 92). The element with atomic number 92 is uranium ((U)).

Answer:

(^{235}_{92}U)