consider the same two pure samples of gas.\nthe particles in sample a have a higher average kinetic energy…

consider the same two pure samples of gas.\nthe particles in sample a have a higher average kinetic energy than the particles in sample b.\nwhich sample has the higher temperature?\nsample a\nsample b\nneither; their temperature is the same

consider the same two pure samples of gas.\nthe particles in sample a have a higher average kinetic energy than the particles in sample b.\nwhich sample has the higher temperature?\nsample a\nsample b\nneither; their temperature is the same

Answer

Explanation:

Step1: Recall kinetic - energy and temperature relation

The average kinetic energy of gas particles is directly proportional to the temperature of the gas. Mathematically, $\overline{K.E.}=\frac{3}{2}kT$, where $\overline{K.E.}$ is the average kinetic energy of the particles, $k$ is the Boltzmann constant, and $T$ is the temperature.

Step2: Compare kinetic energies and temperatures

Since the particles in sample A have a higher average kinetic energy than the particles in sample B, and average kinetic energy is directly proportional to temperature, sample A has a higher temperature.

Answer:

sample A