3) if i contain 3 moles of gas in a container with a volume of 60 liters and at a temperature of 400 k, what…

Explanation:

Step1: Identify the ideal - gas law

The ideal - gas law is $PV = nRT$, where $P$ is pressure, $V$ is volume, $n$ is the number of moles, $R$ is the ideal - gas constant ($R=0.0821\ L\cdot atm/(mol\cdot K)$), and $T$ is temperature.

Step2: Rearrange the formula for pressure

We want to find $P$, so we can rewrite the ideal - gas law as $P=\frac{nRT}{V}$.

Step3: Substitute the given values

Given $n = 3\ mol$, $T = 400\ K$, $V=60\ L$, and $R = 0.0821\ L\cdot atm/(mol\cdot K)$. $P=\frac{3\ mol\times0.0821\ L\cdot atm/(mol\cdot K)\times400\ K}{60\ L}$

Step4: Calculate the pressure

First, calculate the numerator: $3\times0.0821\times400 = 98.52$. Then, divide by the denominator: $P=\frac{98.52}{60}=1.642\ atm$.

Answer:

$1.642\ atm$