a copper rod that has a mass of 200.0 g has an initial temperature of 20.0°c and is heated to 40.0°c. if…
a copper rod that has a mass of 200.0 g has an initial temperature of 20.0°c and is heated to 40.0°c. if 1,540 j of heat are needed to heat the rod, what is the specific heat of copper? use $q = mc_pdelta t$.\n0.0130 j/(g°c)\n0.0649 j/(g°c)\n0.193 j/(g°c)\n0.385 j/(g°c)
Answer
Explanation:
Step1: Identify given values
$q = 1540\ J$, $m=200.0\ g$, $\Delta T=T_{final}-T_{initial}=40.0^{\circ}C - 20.0^{\circ}C=20.0^{\circ}C$
Step2: Rearrange the heat - capacity formula
The formula is $q = mC_{p}\Delta T$. We need to solve for $C_{p}$, so $C_{p}=\frac{q}{m\Delta T}$
Step3: Substitute values
$C_{p}=\frac{1540\ J}{200.0\ g\times20.0^{\circ}C}$
Step4: Calculate the result
$C_{p}=\frac{1540}{4000}\ J/(g\cdot^{\circ}C)= 0.385\ J/(g\cdot^{\circ}C)$
Answer:
0.385 J/(g°C)