a cube of iron ($c_p = 0.450 j/gcdot^{circ}c$) with a mass of 55.8 g is heated from 25.0$^{circ}c$ to…

a cube of iron ($c_p = 0.450 j/gcdot^{circ}c$) with a mass of 55.8 g is heated from 25.0$^{circ}c$ to 49.0$^{circ}c$. how much heat is required for this process? round your answer to three significant figures. use the formula $q = mc_pdelta t$.

a cube of iron ($c_p = 0.450 j/gcdot^{circ}c$) with a mass of 55.8 g is heated from 25.0$^{circ}c$ to 49.0$^{circ}c$. how much heat is required for this process? round your answer to three significant figures. use the formula $q = mc_pdelta t$.

Answer

Explanation:

Step1: Calculate temperature change

$\Delta T=T_2 - T_1=49.0^{\circ}C - 25.0^{\circ}C = 24.0^{\circ}C$

Step2: Substitute values into formula

$q = mC_p\Delta T$, where $m = 55.8\ g$, $C_p=0.450\ J/g\cdot^{\circ}C$, $\Delta T = 24.0^{\circ}C$ $q=55.8\ g\times0.450\ J/g\cdot^{\circ}C\times24.0^{\circ}C$ $q = 55.8\times0.450\times24.0\ J$ $q=602.64\ J$

Step3: Round to three significant figures

$q\approx603\ J$

Answer:

$603$