what is the current in a circuit with a 9.0 v battery and a resistance of 36.0 ω?\n0.25 a\n4.0 a\n45 a\n324 a

Explanation:

Step1: Recall Ohm's law

Ohm's law is $I=\frac{V}{R}$, where $I$ is current, $V$ is voltage, and $R$ is resistance.

Step2: Substitute given values

Given $V = 9.0\ V$ and $R=36.0\ \Omega$. So $I=\frac{9.0}{36.0}$.

Step3: Calculate the current

$I = 0.25\ A$.

Answer:

A. 0.25 A