how does the current in a circuit change if the resistance is doubled?\nthe current is halved.\nthe current…

Answer:

The current is halved.

Explanation:

Step1: Recall Ohm's Law

$V = IR$ (where $V$ is voltage, $I$ is current, $R$ is resistance)

Step2: Express current in terms of voltage and resistance

$I=\frac{V}{R}$

Step3: Consider new resistance

Let the original resistance be $R_1$ and current be $I_1=\frac{V}{R_1}$. The new resistance $R_2 = 2R_1$.

Step4: Calculate new current

$I_2=\frac{V}{R_2}=\frac{V}{2R_1}=\frac{1}{2}\times\frac{V}{R_1}=\frac{1}{2}I_1$. So the current is halved.