current 1 of 8.4 a runs for 240 seconds and then stops. current 2 is 10.5 a. how long does current 2 have to…

current 1 of 8.4 a runs for 240 seconds and then stops. current 2 is 10.5 a. how long does current 2 have to run to deliver the same amount of charge as current 1?\n88.2 s\n192 s\n2016 s\n21,000 s

current 1 of 8.4 a runs for 240 seconds and then stops. current 2 is 10.5 a. how long does current 2 have to run to deliver the same amount of charge as current 1?\n88.2 s\n192 s\n2016 s\n21,000 s

Answer

Explanation:

Step1: Calculate charge of current 1

Use formula $Q = I\times t$, where $I = 8.4$ A and $t = 240$ s. So $Q_1=8.4\times240 = 2016$ C.

Step2: Calculate time for current 2

Since $Q_2 = Q_1$ and $Q_2=I_2\times t_2$, with $I_2 = 10.5$ A and $Q_2 = 2016$ C. Then $t_2=\frac{Q_2}{I_2}=\frac{2016}{10.5}=192$ s.

Answer:

192 s