the current in the wires of a circuit is 120.0 milliamps. if the voltage impressed across the ends of the…

the current in the wires of a circuit is 120.0 milliamps. if the voltage impressed across the ends of the circuit were doubled (with no change in its resistance), then its new current would be ______ milliamps.

the current in the wires of a circuit is 120.0 milliamps. if the voltage impressed across the ends of the circuit were doubled (with no change in its resistance), then its new current would be ______ milliamps.

Answer

Explanation:

Step1: Recall Ohm's Law

Ohm's Law is $I = \frac{V}{R}$, where $I$ is current, $V$ is voltage and $R$ is resistance.

Step2: Analyze the initial and new - voltage situation

Let the initial voltage be $V_1$, current $I_1 = 120$ mA and resistance $R$. So $I_1=\frac{V_1}{R}=120$. The new voltage $V_2 = 2V_1$ and resistance remains $R$. The new current $I_2=\frac{V_2}{R}=\frac{2V_1}{R}$.

Step3: Calculate the new current

Since $I_1=\frac{V_1}{R}=120$ mA and $I_2=\frac{2V_1}{R}$, then $I_2 = 2I_1$. Substituting $I_1 = 120$ mA, we get $I_2=2\times120 = 240$ mA.

Answer:

240