a cylindrical container has a radius of 0.2 m and a height of 1 m. the container is filled with honey. the…

a cylindrical container has a radius of 0.2 m and a height of 1 m. the container is filled with honey. the density of honey is 1417 kg/m³. what is the mass of the honey in the container? enter your answer in the box. use 3.14 for π. round your final answer to the nearest whole number.

a cylindrical container has a radius of 0.2 m and a height of 1 m. the container is filled with honey. the density of honey is 1417 kg/m³. what is the mass of the honey in the container? enter your answer in the box. use 3.14 for π. round your final answer to the nearest whole number.

Answer

Explanation:

Step1: Calculate the volume of the cylinder

The formula for the volume of a cylinder is $V=\pi r^{2}h$. Given $r = 0.2$ m, $h=1$ m and $\pi = 3.14$. So $V=3.14\times(0.2)^{2}\times1=3.14\times0.04\times1 = 0.1256$ $m^{3}$.

Step2: Calculate the mass of the honey

The formula for density is $\rho=\frac{m}{V}$, where $\rho$ is density, $m$ is mass and $V$ is volume. Rearranging for $m$ gives $m=\rho V$. Given $\rho = 1417$ kg/$m^{3}$ and $V = 0.1256$ $m^{3}$. So $m=1417\times0.1256=178.9752$ kg.

Step3: Round the result

Rounding $178.9752$ to the nearest whole number gives $179$ kg.

Answer:

179