date section postlaboratory assignment 1. ether floats on water, and water floats on mercury, as shown in…

date section postlaboratory assignment 1. ether floats on water, and water floats on mercury, as shown in the following diagram. ether (d = 0.714 g/ml) water (d = 1.00 g/ml) mercury (d = 13.6 g/ml) indicate on the above diagram where each of the following would come to rest after being dropped into the glass cylinder. (a) a glass marble (d = 2.95 g/cm³) (b) a platinum ring (d = 21.45 g/cm³) (c) a lump of coal (d = 0.83 g/cm³) (d) a champagne cork (d = 0.19 g/cm³) 2. a 250 - ml flask and stopper have a mass of 110.525 g. a 50.0 - ml sample of gasoline is pipetted into the flask, giving a total mass of 146.770 g. find the density of the gasoline.

date section postlaboratory assignment 1. ether floats on water, and water floats on mercury, as shown in the following diagram. ether (d = 0.714 g/ml) water (d = 1.00 g/ml) mercury (d = 13.6 g/ml) indicate on the above diagram where each of the following would come to rest after being dropped into the glass cylinder. (a) a glass marble (d = 2.95 g/cm³) (b) a platinum ring (d = 21.45 g/cm³) (c) a lump of coal (d = 0.83 g/cm³) (d) a champagne cork (d = 0.19 g/cm³) 2. a 250 - ml flask and stopper have a mass of 110.525 g. a 50.0 - ml sample of gasoline is pipetted into the flask, giving a total mass of 146.770 g. find the density of the gasoline.

Answer

Explanation:

Step1: Find mass of gasoline

Mass of gasoline = Total mass - Mass of flask and stopper. So, $m = 146.770 - 110.525=36.245$ g.

Step2: Recall density formula

The density formula is $\rho=\frac{m}{V}$, where $\rho$ is density, $m$ is mass and $V$ is volume.

Step3: Calculate density of gasoline

Given $V = 50.0$ mL and $m = 36.245$ g. Then $\rho=\frac{36.245}{50.0}=0.7249$ g/mL.

Answer:

$0.7249$ g/mL