a decibel is a logarithmic unit that can be used to measure the intensity of a sound. the function y =…

a decibel is a logarithmic unit that can be used to measure the intensity of a sound. the function y = 10logx gives the intensity of a sound in decibels, where x is the ratio of the intensity of the sound to a reference intensity. the reference intensity is generally set at the threshold of hearing. use the graphing utility to graph the decibel function. the sound intensity of rustling leaves is 100 times the reference intensity. use your graph to determine the sound intensity of rustling leaves in decibels. 20 decibels complete a whisper has a sound intensity of 30 decibels. use your graph to help you complete the following statement. the sound intensity of a whisper is times the reference intensity. done

a decibel is a logarithmic unit that can be used to measure the intensity of a sound. the function y = 10logx gives the intensity of a sound in decibels, where x is the ratio of the intensity of the sound to a reference intensity. the reference intensity is generally set at the threshold of hearing. use the graphing utility to graph the decibel function. the sound intensity of rustling leaves is 100 times the reference intensity. use your graph to determine the sound intensity of rustling leaves in decibels. 20 decibels complete a whisper has a sound intensity of 30 decibels. use your graph to help you complete the following statement. the sound intensity of a whisper is times the reference intensity. done

Answer

Explanation:

Step1: Recall the decibel - intensity formula

The formula for sound intensity in decibels is $y = 10\log x$, where $y$ is the sound - intensity in decibels and $x$ is the ratio of the intensity of the sound to the reference intensity.

Step2: Solve for $x$ when $y = 30$

We are given $y = 30$ and the formula $y=10\log x$. Substitute $y = 30$ into the formula: $30 = 10\log x$. First, divide both sides of the equation by 10: $\frac{30}{10}=\log x$, so $\log x = 3$. Since $\log x$ is the common logarithm (base - 10 logarithm), if $\log x = 3$, then by the definition of logarithms $x = 10^{3}$ (because if $\log_{a}b=c$, then $b = a^{c}$, and for common logarithm $a = 10$).

Answer:

1000