define: momentum. 10) a 8 kg tire is rolled with a velocity of 25 m/s. what is the momentum of the tire? the…

define: momentum. 10) a 8 kg tire is rolled with a velocity of 25 m/s. what is the momentum of the tire? the momentum of the tire was 800 kg(m)/s. 11) a cyclist with a mass of 43 kg is riding a 7 kg bicycle with a velocity of 5 m/s. what is the total momentum of the cyclist and bicycle? the total momentum of the cyclist and bicycle was ____ kg(m)/s. p = m(v) p = m(v)

define: momentum. 10) a 8 kg tire is rolled with a velocity of 25 m/s. what is the momentum of the tire? the momentum of the tire was 800 kg(m)/s. 11) a cyclist with a mass of 43 kg is riding a 7 kg bicycle with a velocity of 5 m/s. what is the total momentum of the cyclist and bicycle? the total momentum of the cyclist and bicycle was ____ kg(m)/s. p = m(v) p = m(v)

Answer

Explanation:

Step1: Recall momentum formula

The formula for momentum is $P = M\times V$, where $P$ is momentum, $M$ is mass and $V$ is velocity.

Step2: Solve for tire's momentum

Given $M = 8\ kg$ and $V=25\ m/s$, substitute into the formula: $P = 8\times25$. $P = 200\ kg(m)/s$

Step3: Solve for cyclist - bicycle system's momentum

The total mass of the cyclist - bicycle system is $M_{total}=43 + 7=50\ kg$ and $V = 5\ m/s$. Using $P = M\times V$, we have $P=50\times5$. $P = 250\ kg(m)/s$

Answer:

The momentum of the tire is $200\ kg(m)/s$. The total momentum of the cyclist and bicycle is $250\ kg(m)/s$.