defining density\ndirections: use the information in each problem to calculate the materials volume and…
defining density\ndirections: use the information in each problem to calculate the materials volume and density.\na rectangular block of cheese measures 10 cm by 5 cm by 3 cm and has a mass of 75 grams. what is the density of the cheese?\nvolume\nf: v = l x w x h\ns:\ne:\ndensity\nf: d = m / v\ns:\ne:\na rectangular bag of sugar has dimensions of 20 cm by 15 cm by 5 cm and a mass of 350 grams. what is the density of the sugar?\nvolume\nf:\ns:\ne:\ndensity\nf:\ns:\ne:\na bar of soap measures 20 cm by 5 cm by 3 cm and has a mass of 120 grams. what is the density of the soap?\nvolume\nf:\ns:\ne:\ndensity\nf:\ns:\ne:
Answer
Problem 1: Cheese
Explanation:
Step1: Calculate volume
$V = L\times W\times H=10\times5\times3 = 150$ $cm^{3}$
Step2: Calculate density
$D=\frac{M}{V}=\frac{75}{150}=0.5$ $g/cm^{3}$
Answer:
$0.5$ $g/cm^{3}$
Problem 2: Sugar
Explanation:
Step1: Calculate volume
$V = L\times W\times H = 20\times15\times5=1500$ $cm^{3}$
Step2: Calculate density
$D=\frac{M}{V}=\frac{350}{1500}=\frac{7}{30}\approx0.23$ $g/cm^{3}$
Answer:
$\frac{7}{30}$ $g/cm^{3}$ (or approximately $0.23$ $g/cm^{3}$)
Problem 3: Soap
Explanation:
Step1: Calculate volume
$V = L\times W\times H=20\times5\times3 = 300$ $cm^{3}$
Step2: Calculate density
$D=\frac{M}{V}=\frac{120}{300}=0.4$ $g/cm^{3}$
Answer:
$0.4$ $g/cm^{3}$