d = m/v\nd = density in (g/cm³ or g cm⁻³) (g/ml or g ml⁻¹) (kg/m³ or kg m⁻³)\nm = mass in (g)\nv = volume in…

d = m/v\nd = density in (g/cm³ or g cm⁻³) (g/ml or g ml⁻¹) (kg/m³ or kg m⁻³)\nm = mass in (g)\nv = volume in (cm³ or ml) note that 1 ml = 1 cm³\nas the mass of an object increases, the density of that object ____________.\nas the volume of that object increases, the density of that object ____________.\npure water has a density of 1.00 g cm⁻³. anything larger than this number will ________ while any object with a density lower than this number would ________.\nwe measure the mass of an object with the use of a ____________.\nthe volume of an object that is a liquid can be measured with the use of a ____________.\nthe volume of an object that are solids and have a square or rectangular shape can be measured by measuring the sides and multiplying them (v = l x w x h) (be sure to measure in cm).\nlevel 1 practice problems: (set up the problem, give answer and units):\n1. if an object had a mass of 345 g and took up a space of 100 ml, then what would be the density?\n2. if an object had a mass of 70 g and took up a space of 1500 cm³, then what would be the density?\n3. if an object took up 500 cm³ of space and had a mass of 15 g, then what would be the density?\n4. would any of these objects float on pure water? explain your answer.

d = m/v\nd = density in (g/cm³ or g cm⁻³) (g/ml or g ml⁻¹) (kg/m³ or kg m⁻³)\nm = mass in (g)\nv = volume in (cm³ or ml) note that 1 ml = 1 cm³\nas the mass of an object increases, the density of that object ____________.\nas the volume of that object increases, the density of that object ____________.\npure water has a density of 1.00 g cm⁻³. anything larger than this number will ________ while any object with a density lower than this number would ________.\nwe measure the mass of an object with the use of a ____________.\nthe volume of an object that is a liquid can be measured with the use of a ____________.\nthe volume of an object that are solids and have a square or rectangular shape can be measured by measuring the sides and multiplying them (v = l x w x h) (be sure to measure in cm).\nlevel 1 practice problems: (set up the problem, give answer and units):\n1. if an object had a mass of 345 g and took up a space of 100 ml, then what would be the density?\n2. if an object had a mass of 70 g and took up a space of 1500 cm³, then what would be the density?\n3. if an object took up 500 cm³ of space and had a mass of 15 g, then what would be the density?\n4. would any of these objects float on pure water? explain your answer.

Answer

Explanation:

Step1: Identificar la fórmula de densidad

La densidad ($D$) se calcula con la fórmula $D=\frac{M}{V}$, donde $M$ es la masa y $V$ es el volumen.

Step2: Resolver el problema 1

Dados $M = 345\ g$ y $V=100\ mL = 100\ cm^{3}$, entonces $D=\frac{345\ g}{100\ cm^{3}} = 3.45\ g/cm^{3}$.

Step3: Resolver el problema 2

Dados $M = 70\ g$ y $V = 1500\ cm^{3}$, entonces $D=\frac{70\ g}{1500\ cm^{3}}\approx0.047\ g/cm^{3}$.

Step4: Resolver el problema 3

Dados $M = 15\ g$ y $V = 500\ cm^{3}$, entonces $D=\frac{15\ g}{500\ cm^{3}}=0.03\ g/cm^{3}$.

Step5: Resolver el problema 4

El objeto del problema 1 tiene una densidad de $3.45\ g/cm^{3}$, que es mayor que la densidad del agua pura ($1.00\ g/cm^{3}$), entonces se hunde. Los objetos de los problemas 2 y 3 tienen densidades ($0.047\ g/cm^{3}$ y $0.03\ g/cm^{3}$ respectivamente) menores que la del agua pura, entonces flotan.

Answer:

  1. $D = 3.45\ g/cm^{3}$
  2. $D\approx0.047\ g/cm^{3}$
  3. $D = 0.03\ g/cm^{3}$
  4. El objeto del problema 1 se hunde, los objetos de los problemas 2 y 3 flotan porque la densidad del objeto 1 es mayor que la del agua pura y las densidades de los objetos 2 y 3 son menores que la del agua pura.