density practice\n1. an object has a volume of 15.2 cm3 and a mass of 45.5 g. what is its density?\n2. an…

density practice\n1. an object has a volume of 15.2 cm3 and a mass of 45.5 g. what is its density?\n2. an object has a volume of 22.5 cm³ and a mass of 75.3 g. what is its density?\n3. a metal ball has a mass of 158 g and occupies a volume of 62.6 cm³. find its density.\n4. an unknown liquid weighs 133g and has a volume of 37.2 ml. what is the density of the liquid?\n5. if a substance has a mass of 117g and a density of 2.761 g/cm³, what is its volume?\n6. a piece of wood has a density of 6.80 g/cm³ and a volume of 4.20 cm³. what is its mass?\n7. a glass container holds 375 g of liquid. if the liquids density is 1.01 g/cm³, what is its volume?\n8. a piece of wood has a density of 2.8 g/cm³ and a volume of 318 cm³. what is its mass?\n9. the mass of a rock is 5.60 kilograms, and its volume is 254 ml. what is the density in g/ml?\n10. the mass of a block of wood is 4.25 x10³ mg, and its volume is 2.2 l. what is the density in g/ml?\n11. the mass of a liquid sample is 3.75 hectograms, and its volume is 1.38 l. what is the density in g/ml?\n12. a rectangular block of metal measures 4.5 cm × 2.5 cm × 1.5 cm and has a mass of 118 g. what is its density in g/cm³?\n13. a solid cylinder has a radius of 1.25 cm and a height of 8.00 cm. its mass is 214 g. what is its density in g/cm³?\n14. a rectangular block of aluminum measures 6.0 cm × 4.0 cm × 2.5 cm and has a mass of 162 g.\n15. a cylindrical rod has a radius of 3.5 cm and a height of 15.0 cm. its mass is 364 g. find its density in g/cm3.\n16. a sample of 27.6 g of silver beads is added to a graduated cylinder containing 18.0 ml of water. the water level rises to the 23.2 ml mark.\n17. a student drops 45.2 g of copper pellets into a graduated cylinder with 50.0 ml of water. the water level rises to the 55.1 ml mark. calculate the density of copper.\n18. a piece of zinc weighing 72.5 g is placed in a graduated cylinder containing 22.0 ml of water. the water level rises to the 32.8 ml mark.

Answer

Explanation:

Step1: Recall density formula

The density formula is $\rho=\frac{m}{V}$, where $\rho$ is density, $m$ is mass and $V$ is volume.

Step2: Substitute values

Given $m = 45.5\ g$ and $V=15.2\ cm^{3}$, then $\rho=\frac{45.5}{15.2}\ g/cm^{3}\approx 2.99\ g/cm^{3}$

Answer:

$2.99\ g/cm^{3}$

Explanation:

Step1: Use density formula

$\rho=\frac{m}{V}$

Step2: Plug - in values

$m = 75.3\ g$ and $V = 22.5\ cm^{3}$, so $\rho=\frac{75.3}{22.5}\ g/cm^{3}\approx3.35\ g/cm^{3}$

Answer:

$3.35\ g/cm^{3}$

Explanation:

Step1: Apply density formula

$\rho=\frac{m}{V}$

Step2: Substitute given values

$m = 158\ g$ and $V=62.6\ cm^{3}$, then $\rho=\frac{158}{62.6}\ g/cm^{3}\approx 2.52\ g/cm^{3}$

Answer:

$2.52\ g/cm^{3}$

Explanation:

Step1: Recall density formula

$\rho=\frac{m}{V}$

Step2: Insert values

$m = 133\ g$ and $V = 37.2\ mL$, so $\rho=\frac{133}{37.2}\ g/mL\approx3.58\ g/mL$

Answer:

$3.58\ g/mL$

Explanation:

Step1: Rearrange density formula for volume

$V=\frac{m}{\rho}$

Step2: Substitute values

$m = 117\ g$ and $\rho=2.761\ g/cm^{3}$, then $V=\frac{117}{2.761}\ cm^{3}\approx42.4\ cm^{3}$

Answer:

$42.4\ cm^{3}$

Explanation:

Step1: Use mass - density - volume relation

$m=\rho V$

Step2: Substitute values

$\rho = 6.80\ g/cm^{3}$ and $V = 4.20\ cm^{3}$, so $m=6.80\times4.20\ g = 28.6\ g$

Answer:

$28.6\ g$

Explanation:

Step1: Rearrange density formula for volume

$V=\frac{m}{\rho}$

Step2: Substitute values

$m = 375\ g$ and $\rho=1.01\ g/cm^{3}$, then $V=\frac{375}{1.01}\ cm^{3}\approx371\ cm^{3}$

Answer:

$371\ cm^{3}$

Explanation:

Step1: Apply mass formula

$m=\rho V$

Step2: Substitute values

$\rho = 2.8\ g/cm^{3}$ and $V = 318\ cm^{3}$, so $m=2.8\times318\ g=890.4\ g$

Answer:

$890.4\ g$

Explanation:

Step1: Convert mass to grams

$m = 5.60\ kg=5600\ g$

Step2: Use density formula

$\rho=\frac{m}{V}$, with $V = 254\ mL$, so $\rho=\frac{5600}{254}\ g/mL\approx22.0\ g/mL$

Answer:

$22.0\ g/mL$

Explanation:

Step1: Convert mass to grams

$m = 4.25\times10^{3}\ mg = 4.25\ g$

Step2: Convert volume to mL

$V = 2.2\ L=2200\ mL$

Step3: Calculate density

$\rho=\frac{m}{V}=\frac{4.25}{2200}\ g/mL\approx0.00193\ g/mL$

Answer:

$0.00193\ g/mL$

Explanation:

Step1: Convert mass to grams

$m = 3.75\ hg=375\ g$

Step2: Convert volume to mL

$V = 1.38\ L = 1380\ mL$

Step3: Calculate density

$\rho=\frac{m}{V}=\frac{375}{1380}\ g/mL\approx0.272\ g/mL$

Answer:

$0.272\ g/mL$

Explanation:

Step1: Calculate volume of rectangular block

$V=4.5\times2.5\times1.5\ cm^{3}=16.875\ cm^{3}$

Step2: Use density formula

$\rho=\frac{m}{V}$, with $m = 118\ g$, so $\rho=\frac{118}{16.875}\ g/cm^{3}\approx7.0\ g/cm^{3}$

Answer:

$7.0\ g/cm^{3}$

Explanation:

Step1: Calculate volume of cylinder

$V=\pi r^{2}h$, where $r = 1.25\ cm$ and $h = 8.00\ cm$, so $V=\pi\times(1.25)^{2}\times8.00\ cm^{3}\approx39.27\ cm^{3}$

Step2: Calculate density

$\rho=\frac{m}{V}$, with $m = 214\ g$, so $\rho=\frac{214}{39.27}\ g/cm^{3}\approx5.45\ g/cm^{3}$

Answer:

$5.45\ g/cm^{3}$

Explanation:

Step1: Calculate volume of rectangular block

$V=6.0\times4.0\times2.5\ cm^{3}=60\ cm^{3}$

Step2: Use density formula

$\rho=\frac{m}{V}$, with $m = 162\ g$, so $\rho=\frac{162}{60}\ g/cm^{3}=2.7\ g/cm^{3}$

Answer:

$2.7\ g/cm^{3}$

Explanation:

Step1: Calculate volume of cylinder

$V=\pi r^{2}h$, with $r = 3.5\ cm$ and $h = 15.0\ cm$, so $V=\pi\times(3.5)^{2}\times15.0\ cm^{3}\approx577.2\ cm^{3}$

Step2: Calculate density

$\rho=\frac{m}{V}$, with $m = 364\ g$, so $\rho=\frac{364}{577.2}\ g/cm^{3}\approx0.63\ g/cm^{3}$

Answer:

$0.63\ g/cm^{3}$

Explanation:

Step1: Calculate volume of silver beads

$V=23.2 - 18.0\ mL = 5.2\ mL$

Step2: Calculate density

$\rho=\frac{m}{V}$, with $m = 27.6\ g$, so $\rho=\frac{27.6}{5.2}\ g/mL\approx5.31\ g/mL$

Answer:

$5.31\ g/mL$

Explanation:

Step1: Calculate volume of copper pellets

$V=55.1 - 50.0\ mL = 5.1\ mL$

Step2: Calculate density

$\rho=\frac{m}{V}$, with $m = 45.2\ g$, so $\rho=\frac{45.2}{5.1}\ g/mL\approx8.86\ g/mL$

Answer:

$8.86\ g/mL$

Explanation:

Step1: Calculate volume of zinc

$V=32.8 - 22.0\ mL = 10.8\ mL$

Step2: Calculate density

$\rho=\frac{m}{V}$, with $m = 72.5\ g$, so $\rho=\frac{72.5}{10.8}\ g/mL\approx6.71\ g/mL$

Answer:

$6.71\ g/mL$