the density of silver is 10.49 g/cm³, and the density of gold is 19.32 g/cm³. what mass of gold will have…

Explanation:

Step1: Calculate volume of silver

Use the density formula $\rho=\frac{m}{V}$, so $V = \frac{m}{\rho}$. For silver, $m = 12$ g and $\rho_{silver}=10.49$ g/cm³. Then $V_{silver}=\frac{12}{10.49}\text{ cm}^3$.

Step2: Calculate mass of gold

Since $V_{gold}=V_{silver}$, and for gold $\rho_{gold} = 19.32$ g/cm³, using $m=\rho V$, we have $m_{gold}=\rho_{gold}\times V_{gold}=19.32\times\frac{12}{10.49}$. $m_{gold}=\frac{19.32\times12}{10.49}=\frac{231.84}{10.49}\approx22.10$ g

Answer:

22.10 g