1 - 5 density worksheet\nsince density shows how many particles (mass) are in a certain amount of space…

1 - 5 density worksheet\nsince density shows how many particles (mass) are in a certain amount of space (volume), the formula for density is...\ndensity = mass / volume (mass divided by volume)\nthe unit for density is grams per cubic centimeter (g/cm³)\ncalculate the densities of the following objects. you will need a calculator.\nround all answers to the tenths place (1 place after the decimal)\n7. a shoe - box\nmass = 114.0 g volume = 538.5 cm³\ndensity = ______ g/cm³\n8. a rock\nmass = 22.3 g volume = 8.0 cm³\ndensity = ______ g/cm³\n9. a full soda bottle\nmass = 609.0 g volume = 591.0 ml\n10. a dry sponge\nmass = 54.2 g volume = 78.1 cm³\ndensity = ______ g/cm³\n11. when a dry sponge absorbs water, which changes most (circle one)?\na. the sponge’s mass\nb. neither changes, mass and volume stay the same\nc. the sponge’s volume\n12. the sponge in question #10 absorbs 277 grams of water. recalculate its density.\n*show your work\n13. a) you drink all of the soda out of the bottle (from question #9). the soda had a mass of 570 grams. recalculate the density of the empty soda bottle.\n*show your work\nb) why did the density of the bottle of soda change?
Answer
Explanation:
Step1: Recall density formula
Density $\rho=\frac{m}{V}$, where $m$ is mass and $V$ is volume.
Step2: Calculate density of shoe - box
Given $m = 114.0$ g and $V=538.5$ $cm^{3}$. Then $\rho=\frac{114.0}{538.5}\approx0.2$ g/$cm^{3}$.
Step3: Calculate density of rock
Given $m = 22.3$ g and $V = 8.0$ $cm^{3}$. Then $\rho=\frac{22.3}{8.0}=2.8$ g/$cm^{3}$.
Step4: Convert volume of soda bottle to $cm^{3}$
Since $1$ mL=$1$ $cm^{3}$, for a soda - bottle with $V = 591.0$ mL, $V = 591.0$ $cm^{3}$. Given $m = 609.0$ g, then $\rho=\frac{609.0}{591.0}\approx1.0$ g/$cm^{3}$.
Step5: Calculate density of dry sponge
Given $m = 54.2$ g and $V = 78.1$ $cm^{3}$. Then $\rho=\frac{54.2}{78.1}\approx0.7$ g/$cm^{3}$.
Step6: Answer question 11
When a dry sponge absorbs water, its mass increases significantly while its volume changes very little. So the answer is A. the sponge's mass.
Step7: Recalculate density of sponge after absorbing water
New mass $m_{new}=54.2 + 277=331.2$ g, volume $V = 78.1$ $cm^{3}$. Then $\rho=\frac{331.2}{78.1}\approx4.2$ g/$cm^{3}$.
Step8: Calculate mass of empty soda bottle
Mass of full - soda bottle is $m_{full}=609.0$ g, mass of soda is $m_{soda}=570$ g. So mass of empty bottle $m_{empty}=609.0 - 570 = 39$ g, volume $V = 591.0$ $cm^{3}$. Then $\rho=\frac{39}{591.0}\approx0.1$ g/$cm^{3}$.
Step9: Answer part b of question 13
The density of the bottle of soda changed because the mass of the substance inside the bottle changed (from full of soda to empty), while the volume of the bottle remained the same.
Answer:
- $0.2$ g/$cm^{3}$
- $2.8$ g/$cm^{3}$
- $1.0$ g/$cm^{3}$
- $0.7$ g/$cm^{3}$
- A. the sponge's mass
- $4.2$ g/$cm^{3}$
- a) $0.1$ g/$cm^{3}$ b) The mass of the substance inside the bottle changed while the volume remained the same.