determining the density of a sphere\nthe density of water is 1 gram per cubic centimeter. a more dense…

determining the density of a sphere\nthe density of water is 1 gram per cubic centimeter. a more dense object will sink, and a less dense object will float. will a marble with a radius of 1.4 cm and a mass of 9 grams sink or float in water?\nthe marble will because the density of the marble is about grams per cubic centimeter.

determining the density of a sphere\nthe density of water is 1 gram per cubic centimeter. a more dense object will sink, and a less dense object will float. will a marble with a radius of 1.4 cm and a mass of 9 grams sink or float in water?\nthe marble will because the density of the marble is about grams per cubic centimeter.

Answer

Explanation:

Step1: Calculate volume of sphere

The volume formula for a sphere is $V = \frac{4}{3}\pi r^{3}$. Given $r = 1.4$ cm, so $V=\frac{4}{3}\pi(1.4)^{3}$. $V=\frac{4}{3}\pi\times2.744\approx\frac{4}{3}\times3.14\times2.744\approx11.49$ $cm^{3}$.

Step2: Calculate density of marble

Density formula is $\rho=\frac{m}{V}$. Given $m = 9$ grams and $V\approx11.49$ $cm^{3}$, so $\rho=\frac{9}{11.49}\approx0.78$ g/$cm^{3}$.

Step3: Compare with water density

The density of water is 1 g/$cm^{3}$. Since $0.78< 1$, the marble will float.

Answer:

float; 0.78