determining the net force\nconsider a sign suspended on a boom that is supported by a cable, as shown. what…

determining the net force\nconsider a sign suspended on a boom that is supported by a cable, as shown. what is the proper equation to use for finding the net force in the y - direction?\n$f_{nety}=(f_t)(\\sin32^{circ})+f_g$\n$f_{nety}=(f_t)(\\sin32^{circ})-f_g$\n$f_{nety}=(f_t)(\\cos32^{circ})+f_g$\n$f_{nety}=(f_t)(\\cos32^{circ})-f_g$

determining the net force\nconsider a sign suspended on a boom that is supported by a cable, as shown. what is the proper equation to use for finding the net force in the y - direction?\n$f_{nety}=(f_t)(\\sin32^{circ})+f_g$\n$f_{nety}=(f_t)(\\sin32^{circ})-f_g$\n$f_{nety}=(f_t)(\\cos32^{circ})+f_g$\n$f_{nety}=(f_t)(\\cos32^{circ})-f_g$

Answer

Explanation:

Step1: Resolve tension force in y - direction

The vertical component of the tension force $F_T$ is $F_T\sin32^{\circ}$. The gravitational force $F_g$ acts downwards.

Step2: Determine net - force formula

The net force in the y - direction $F_{nety}$ is the sum of the vertical components of the forces acting on the sign. The upward - acting force is the vertical component of the tension $F_T\sin32^{\circ}$ and the downward - acting force is the gravitational force $F_g$. So, $F_{nety}=(F_T)(\sin32^{\circ})-F_g$.

Answer:

$F_{nety}=(F_T)(\sin32^{\circ})-F_g$ (the second option)