determining velocity\ncalculate the average travel time for each distance, and then use the results to…

determining velocity\ncalculate the average travel time for each distance, and then use the results to calculate.\nnumber of washers trial time to travel 0.25 m t1(s) time to travel 0.50 m t2(s)\n1 washer mass = 4.9 g trial #1 2.24 3.16\ntrial #2 2.21 average 3.08 average\ntrial #3 2.23 3.15\nthe average time that it takes for the car to travel the first 0.25m is s.\nthe average time to travel just between 0.25 m and 0.50 m is s.\ngiven the time taken to travel the second 0.25 m section, the velocity would be m/s.

determining velocity\ncalculate the average travel time for each distance, and then use the results to calculate.\nnumber of washers trial time to travel 0.25 m t1(s) time to travel 0.50 m t2(s)\n1 washer mass = 4.9 g trial #1 2.24 3.16\ntrial #2 2.21 average 3.08 average\ntrial #3 2.23 3.15\nthe average time that it takes for the car to travel the first 0.25m is s.\nthe average time to travel just between 0.25 m and 0.50 m is s.\ngiven the time taken to travel the second 0.25 m section, the velocity would be m/s.

Answer

Explanation:

Step1: Calculate average time for 0.25 m

The formula for the average of a set of numbers $x_1,x_2,x_3$ is $\bar{x}=\frac{x_1 + x_2+x_3}{3}$. Here, $x_1 = 2.24$, $x_2=2.21$, $x_3 = 2.23$. So, $\bar{t_1}=\frac{2.24 + 2.21+2.23}{3}=\frac{6.68}{3}\approx2.23$ s.

Step2: Calculate average time for 0.50 m

Using the same average - formula, with $x_1 = 3.16$, $x_2=3.08$, $x_3 = 3.15$. So, $\bar{t_2}=\frac{3.16+3.08 + 3.15}{3}=\frac{9.39}{3}=3.13$ s.

Step3: Calculate average time for 0.25 - 0.50 m

The time to travel from 0.25 m to 0.50 m is $t=\bar{t_2}-\bar{t_1}$. So, $t = 3.13 - 2.23=0.9$ s.

Step4: Calculate velocity for 0.25 - 0.50 m

The formula for velocity $v=\frac{d}{t}$, where $d = 0.25$ m and $t = 0.9$ s. So, $v=\frac{0.25}{0.9}\approx0.28$ m/s.

Answer:

The average time that it takes for the car to travel the first 0.25m is 2.23 s. The average time to travel just between 0.25 m and 0.50 m is 0.9 s. Given the time taken to travel the second 0.25 m section, the velocity would be 0.28 m/s.